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What is the slope-intercept form of the equation of the line that passes through the points (2, 7) and (4, −1) ?

y=−4x+15
y=−4x+12
y=−4x+30
y=−4x+3

User Thejesh GN
by
7.5k points

2 Answers

5 votes

Find the slope (m) by using Y2-Y1/X2-X1

Y2 = -1

Y1 = 7

X2 = 4

X1 = 2

(-1 - 7)/((4-2) = -8/2 = -4

Use the point-slope formula to determine the equation. You only need to use one set of points. (2,7) in this case.

(y-Y1) = m(x-X1)

(y - 7) = -4(x - 2)

y-7=-4x + 8

y= -4x + 15

User Moleboy
by
9.2k points
4 votes

Find the slope (m) by using Y2-Y1/X2-X1

Y2 = -1

Y1 = 7

X2 = 4

X1 = 2

(-1 - 7)/((4-2) = -8/2 = -4

Use the point-slope formula to determine the equation. You only need to use one set of points. (2,7) in this case.

(y-Y1) = m(x-X1)

(y - 7) = -4(x - 2)

y-7=-4x + 8

y= -4x + 15

User Mahesh Kembhavi
by
8.7k points

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