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I need chemistry help! How would I set up these problems?

I need chemistry help! How would I set up these problems?-example-1
User GetFree
by
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1 Answer

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Answer: -

1) 8.33 minutes

2) 118.39 in/ s

180.43 m/min

10.83 km/ hr

Explanation: -

Speed of light = 3 x 10⁸ m/s

Distance of the earth from the sun= 93 million miles

We know 1 million = 1,000,000

Also 1 mile = 1609 m

Distance of the earth from the sun= 93 million miles

= 93,000,000 miles.

= 1.5 x
10^(11) m

Time taken =
(Distance)/(Speed)

=
\frac{1.5 x [tex] 10^(11) m}{3 x 10⁸ m/s} [/tex]

= 500 s

= 500/ 60

= 8.33 minutes

2) Distance = 1 mile = 63360 inches

Time taken = 8.92 min

= 8.92 x 60

= 535.2 s

Speed =
(distance)/(time)

=
(63360 inches)/(535.2 s)

= 118.39 in/ s

Distance = 1 mile = 63360 inches = 63360 x 2.54 cm = 63360 x 2.54 x
10^(-2) m

Time taken = 8.92 min

Speed =
(distance)/(time)

=
\frac{63360 x 2.54 x [tex] 10^(-2) m}{8.92 min} [/tex]

= 180.43 m/ min

1 m = 10⁻³ Km

1 min = 1/60 hour

1 m /min = 10⁻³ km/
(1)/(60 hour)

= 60/1000

=0.06 km/hr

180.43 m / min = 180 x 0.06 km / hr

= 10.93 km / hr

User Coffeejunk
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