Question

X^2+26x+48=0

What are the solutions?

Answer 1

Hi there!

Let's solve this equation step by step!

`{x}^(2) + 26x + 48 = 0`

First factor the equation. To do this we're looking for two numbers with a product of 48 and a sum of 26. We find the numbers 24 and 2. Let's factor!


`(x + 24)(x + 2) = 0`
Now use the rule AB = 0 gives A = 0 or B = 0.

We find the following:

`x + 24 = 0 \: \: or \: \: x + 2 = 0`

And finally subtract.

`x = - 24 \: \: or \: \: x = - 2`

~ Hope this helps you!