Question

Which quadratic function has one real solution? 0 = 2(x + 7)(x – 5) 0 = (x – 3)(x – 3) 0 = 2.4(x – 2)(x + 2) 0 = (x – 2)(x – 1)

Answer 1

0 = (x – 3)(x – 3)

x - 3 = 0

x = 3

Solution is x = 3 (one real solution)

Answer

0 = (x – 3)(x – 3)

Answer 2

B

Explanation:

0=2/3(x-3)(x-3)

did it on edge