Question

In the acetylene torch, acetylene gas (c2h2) burns in oxygen to produce carbon dioxide and water. 2c2h2(g)+5o2(g)→4co2(g)+2h2o(g) part a how many moles of o2 are needed to react with 3.00 moles c2h2?

Answer 1

Answer: -

In the acetylene torch, 7.5 moles of O₂ are needed to react with 3.00 moles of acetylene gas C₂H₂.

Explanation: -

The balanced chemical equation for this reaction is

2 C₂H₂ + 5 O₂ → 4 CO₂ + 2 H₂O

From the equation we see

2 moles of C₂H₂ react with 5 moles of O₂

3.00 moles of C₂H₂ react with
`(5 moles of O2)/(2 moles of C2H2)` x 3.00 moles of C₂H₂

= 7.5 moles of O₂

Thus, in the acetylene torch, 7.5 moles of O₂ are needed to react with 3.00 moles of acetylene gas C₂H₂.