Question

Three resistors of value 4 ω, 10 ω and 7 ω are placed in parallel. they are connected to a 6 ω resistor in series. what is the equivalent resistance in the circuit?

Answer 1

resistance of 4 ohm, 10 ohm and 7 ohm is connected in parallel.

so net resistance in parallel is given by

`(1)/(R) = (1)/(R_1) + (1)/(R_2) + (1)/(R_3)`

`(1)/(R) = (1)/(4) + (1)/(10) + (1)/(7)`

`R = (140)/(69) ohm`

now it is connected to 6 ohm resistance in series

so net resistance is given by

`R_(net) = R_1 + R_2`

`R_(net) = 6 ohm + (140)/(69) ohm`

`R_(net) = 8.03 ohm`