Question

Find the missing side round to the nearest tenth can someone plz help me

Answer 1

we are given

hypotenuse =x

angle =theta=43

adjacent=y

opposite =141

Calculation of x:

we can use sin formula

`sin(43)=(141)/(x)`

`x=(141)/(sin(43))`

now, we can solve for x

`x=206.7`...........Answer

Calculation of y:

we can use tan formula

`tan(43)=(141)/(y)`

now, we can solve for y

`y=(141)/(tan(43))`

we will get

`y=151.2`............Answer

Answer 2

From the given diagram, we are supposed to find the missing sides.

The given triangle is a right angled Triangle so one angle is 90 and another given angle is 43 degree

Now using the sine rule , we can write

`(Sin43)/(141)=(Sin90)/(x)\\\\\text{Simplify we get}\\\\x= (Sin90)/(sin43)*141\\\\\text{Now substitute the values and simplify we get}\\\\x= (Sin90)/(sin43)*141\\\\x= (1)/(sin43)*141, Sin90=1\\\\x=1.46628*141\approx 206.7`

Now we can write

`image`