Question

What is the width of a box when the length is x+2, the height is x+8, and the volume is x^3+9x^2+6x-16?

Answer 1

(x+2)(x+8) = x^2 +10x +16

(x^2 + 10x + 16)(x-1) = x^3+9x^2+6x-16, so the other dimension is x-1

Answer 2

The given box has the following properties

The length is
`x+2`

The height is
`x+8`

The volume is
`x^3+9x^2+6x-16`

As expression for volume can be setup as below , suppose width is w

`image`

Hence width w=(x-1)