Answer:
1930g
Step-by-step explanation:
We have been given that the salinity of sea water is 3.5%;
Now the mass of sea water sample is 2000g
So, problem here is to find the quantity of pure water in the sample = ?
Solution:
Let us find the quantity of the salt in the sample;
Salt content = 3.5% x 2000 = 70g
Amount of pure water = 2000 - 70 = 1930g