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For all seawater problems, assume the salinity is 3.5%

If you have a 2000 gram sample of seawater, how many grams of pure water are there?
0.035 x 2000) = x, 2000 - x = pure water
Answer to the nearest WHOLE number.

User Gabac
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1 Answer

6 votes

Answer:

1930g

Step-by-step explanation:

We have been given that the salinity of sea water is 3.5%;

Now the mass of sea water sample is 2000g

So, problem here is to find the quantity of pure water in the sample = ?

Solution:

Let us find the quantity of the salt in the sample;

Salt content = 3.5% x 2000 = 70g

Amount of pure water = 2000 - 70 = 1930g

User KenS
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3.3k points