Question

What is the equation of the line that passes through the points (0.8, 0.2) and (0.5, 1.5)

Answer 1

We can write the equation of line in the form

y=mx +b

where m is slope , and b is y intercept

Now the slope formula is

`m= \frac{{(y_(2) - y_(1))}}{{(x_(2) - x_(1))}}`

let's plug the points in the formula to find slope

m=
`((1.5-0.2))/((0.5-0.8)) =(1.3)/(-0.3)= (-13)/(3)`

So we get equation as

`y=(-13)/(3) +b`

Now we have to find the value of b also

to find the value of b , we can plug any one point

`0.2 = (-13)/(3) (0.8) +b`

`0.2= (52)/(15) +b`

`b=(-49)/(15)`

So the equation is

`y=(-13)/(3) x - (49)/(15)`