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A 4.5-m-long wooden board with a 24-kg mass is supported in two places. One support is directly under the center of the board, and the other is at one end. What can be said about the forces exerted by the supports?

2 Answers

2 votes

Answer:

The support at the middle of the board exerts an upward force that is equal to the weight of the board mg ( 24x9.81)N which is 235.44N.

The support at the other end exerts no force on the board since the board is already balanced by the middle support.

Step-by-step explanation:

Detailed explanation and calculation is shown in the image below

A 4.5-m-long wooden board with a 24-kg mass is supported in two places. One support-example-1
User Dertkw
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All the weight of the wooden board is bear by the support located at the centre of the rod, and the other support which is located at the end, will have no reaction force, or 0 reaction force.

Therefore the reaction at the centre support is equal to the weight of the board, while the support at the end has 0 reaction force.

User Ashraff Ali Wahab
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