a > b
A . a^5b^3/ab^4 = a^4/b
B. a^4 / a*a*a*a = a^4 / a^4 = 1
C. ab^2 / a^2b = b/a
D. b*b*b/b^3 = b^3/b^3 = 1
B and D, doesn't matter what values of a and b it's always equal 1
Lets say a = 2 and b = 1
A. a^4/b = 2^4 / 1 = 16/1 = 16
C. b/a = 1/2 = 0.5
So C has the least value
Answer:
ab^2 / a^2b