95.5k views
5 votes
Suppose a bag of marbles has 4 green, 2 red, 5 yellow, 1 brown, and 7 blue marbles. What is the probability of picking a green marble?

User Amir Eldor
by
8.2k points

2 Answers

6 votes
Total number of marbles =19
=>(probability of getting a green marble)=number if green marbles/total number of marbles
=>4/19
Hope this helps.....
User Thomas Lumley
by
8.7k points
2 votes

The bag of marbles has 4 green, 2 red, 5 yellow, 1 brown, and 7 blue marbles.

Total number of marble=4+2+5+1+7=19

The probability P(E) is defined as
P(E)=(n(E))/(n(s))

where n(E) is the total number of favourable events.

and n(s) is the total number of events

Hence for the given data we can write


P(E)=(4)/(19)

Because total number of green marbles = n(E)=4

Total number of Marbles =n(S)=19

Hence P(E)=4/19

User Klaas Van Der Weij
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories