Question

Identify the equation of the circle that has its center at (9, 12) and passes through the origin.

Answer 1

The circle has center at (9, 12) and passes through the origin.

Equation of the circle in center and radius form is given by

`(x-h)^2+(y-k)^2=r^2`

where r is the radius and center at (h,k)

Now substitute the value of the center we get

`(x-9)^2+(y-12)^2=r^2`

As it passes through the origin so we can write

`image`

Hence the equation of the circle is

`(x-9)^2+(y-12)^2=15^2`