Question

What is the vertex of the graph y= x^2 + 6x - 5

Answer 1

we are given

`y= x^2 + 6x - 5`

Firstly ,we can find equation in vertex form

so, we will complete x square

`y= x^2 + 6x+3^2-3^2 - 5`

`y= (x+3)^2-3^2 - 5`

`y= (x+3)^2-14`

now, we can compare it with vertex form of equation

`y= (x-h)^2+k`

we can find h and k

`h=-3 , k=-14`

so, vertex is

`(h,k)=(-3,-14)`.............Answer