Question

Please help need Help ASAP

Answer 1

A (2m , 2n) and C(2p , 2r)

Midpoint

x = (x1+x2)/2 and y = (y1+y2)/2

So midpoint of AC:

x = (2m+2p)/2

= 2(m+p)/2

= m + p

y = (2n+2r)/2

= 2(n + r)/2

= n + r

Answer is the last option

(m + p , n +r)

Answer 2

We apply the mid point formula

That is for two points
`(x_(1) ,y_(1)) and (x_(2),y_(2))`

The mid point is given by

`(((x_(1) + x_(2)))/(2) , ((y_(1) + y_(2)))/(2) )`

So we plug the values

`(((2m + 2p))/(2) , ((2n+2r))/(2) )`

So we can simplify it now factor 2 on both

We get

`(((2(m+p)))/(2) , ((2(n+r)))/(2) )`

we can cancel out the 2 in numerator and denominator

So

`(m+p) , (n+r)`

Final answer is Option D

(m+p),(n+r)