What is the extreme of the following function y = - x^(2) + 2

Question

asked Mar 23, 2019 186k views

1 Answer

Subb · Answer 1 · 2019-03-29T05:06:50+0000

It is a quadratic function with graph as parabola

and its maximum lies at the vertex

So we have to find the vertex

So firstly compare it with y=ax^2 +bx +c

we get a=-1 and b=0 and c=2

So to find the vertex (h,k)

h=(-b)/(2a)= (-0)/(2(-1))= 0

to find k , plug h=0 inplace of x in the function

h=-(0)^2 +2 = 2

So vertex is (0,2)

And the maximum value is (0,2) which is the extreme of the function