Question

A solution is 0.0460 mnabr. what is the molarity of the solution if the density is 1.10 g/ml? a solution is 0.0460 . what is the molarity of the solution if the density is 1.10 ?

Answer 1

Answer: -

0.0506 M

Explanation:-

Let the volume of the solution be 1000 mL

Total mass of the solution = Density of the solution x Volume of the solution

= 1.10 g / mL x 1000 mL

= 1100 g.

Molality is the number of moles present per 1000 g of water.

Molality =0.0460 m

1000 g of the solution has 0.046 moles of NaBr.

1100 g of the solution has
`(0.046 mol x 1100 g)/(1000 g)`

= 0.0506 mol

We started with 1000 mL solution.

We found it to contain 0.0506 mol

Molarity is defined as number of moles of NaBr per 1000mL of the solution.

Molarity of NaBr = 0.0506 M

Answer 2

Answer: The molarity of the solution 0.0503 M.

Step-by-step explanation:

Molality if the solution = 0.0460 m = 0.0460 mol/kg

That is 0.0460 moles of NaBr are present are 1000 g of the water

Mass of the solution = Mass of NaBr + Mass of water

Mass of NaBr = 103 g/mol × 0.0460 mol = 4.738 g

Mass of the solution = 4.738 g + 1000 g = 1004.738 g

Density of the solution: 1.10 g/ml

`Density=\frac{\text{Mass of the solution}}{\text{Volume of the solution}}`

`1.10 g/ml=(1004.738 g)/(V)`

V = 913.39 ml

`Molarity=\frac{\text{Moles of NaBr}}{\text{Volume of the solution in L}}`

`Molarity=(0.0460)/(0.91339 L)=0.0503 mol/L=0.0503 M`

The molarity of the solution 0.0503 M.