Question

A 99-m-long wire carrying a current of 4.1 a will be accompanied by a magnetic field of what strength at a distance of 0.056 m from the wire? (magnetic permeability in empty space µ0 = 4π × 10−7 t⋅m/a)

Answer 1

The magnetic field strength=1.46 x 10⁻⁵ T

Step-by-step explanation:

the magnetic field is given by

B=
`(\mu i)/(2\pi r)`

μo= 4π x 10⁻⁷ Tm/A

i= current= 4.1 A

r=0.056 m

B= (4π x 10⁻⁷)(4.1) / (2π*0.056)

B=1.46 x 10⁻⁵ T