Question

What is the solubility of 2 kg of potassium chloride dissolved into 750 cm3 of water

Answer 1

Answer:- Solubility of KCl solution is 0.36 M.

Solution:- 2 kg of KCl dissolved into
`750cm^3` .

`1cm^3` = 1 mL

So,
`750cm^3` = 750 mL

1000 mL = 1 L

So, 750 mL = 0.75 L

1 kg = 1000 g

So, 2 kg of KCl = 2000 g of KCl

Molar mass of KCl is 74.55 gram per mol.

So, moles of KCl =
`2000g((1mol)/(74.55g))`

= 26.8 mol

Molar solubility of KCl =
`(moles of KCl)/(Liter of solution)`

molar solubility of KCl =
`(26.8 mol)/(0.75 L)`

molar solubility of KCl = 0.36 M