Question

Use triangleABC to find the value of sin B

Answer 1

The given triangle is a right triangle right angled at angle C. For angle B the adjacent side is BC ,the side opposite to angle B is AC while AB is hypotenuse. Sin of any angle is ratio of opposite and hypotenuse.

Sin
`(opposite)/(hypotenuse)`

The opposite in the figure is 24 and hypotenuse is 25

Substituting the values of opposite and hypotenuse from figure we have:

Sin B=
`(24)/(25)`

Answer 2

As we are given

Opposite side of the angle B=24

Hypotenuse =25

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