Question

A merry-go-round starts from rest and reaches the angular speed of 4 rpm in the first two minutes. what would be the angular acceleration of the merry-go-round in rpm/min?

Answer 1

initially marry go round is at rest

after t= 2 minutes its final angular speed is 4 rpm

`w_f = 2 \pi *(4)/(60)`

`w_f = 0.42 rad/s`

now by using kinematics we will have

`w_f = w_0 + \alpha * t`

`0.42 = 0 + \alpha * (2*60)`

`\alpha = 3.5 * 10^(-3) rad/s^2`

`\alpha = 3.5 * 10^(-3) * (60*60)/(2\pi)`

`\alpha = 2 rev/min^2`