The given expression can be written as :
![(x^(2)+3x)/(x^(2)-2x+1) =(x(x+3))/((x-1)(x-1))](https://img.qammunity.org/2019/formulas/mathematics/middle-school/ilrpvq6af0nm8rgfnn8vm9l433he9rw8u0.png)
In the numerator x can be taken as a common factor to give x(x+3x)
In denominator the first factors are x in both the parenthesis .We then find two numbers which when multiplied will give us 1 and the same numbers on addition should give us -2.The numbers are -1 and -1 .These are written next to x in both the parenthesis .The factors of denominator are (x-1)(x-1) .This can not be simplified further.