224k views
4 votes
3/7(b+2)-6/7(b-2)=
CAN SOMEONE HELP SOLVE?

User LeoNerd
by
6.6k points

1 Answer

6 votes

3/7(b+2)-6/7(b-2)=


(3)/(7(b+2)) -(6)/(7(b-2))

Here we find lcd first

lcd = 7(b+2)(b-2)

converting into lcd form we get,


(3(b-2))/(7(b+2)(b-2)) -(6(b+2))/(7(b-2)(b+2))

=
((3b-6))/(7(b+2)(b-2)) -((6b+12))/(7(b-2)(b+2))

=
(3b-6-6b-12)/(7(b+2)(b-2))

=
(-3b-18)/(7(b+2)(b-2))

User Dan Gifford
by
6.9k points