Question

Force x has a magnitude of 1210 ​pounds, and force y has a magnitude of 1540 pounds. they act on a single point at an angle of 15 degrees to each other. find the magnitude of the equilibrant and the angle between the equilibrant and the 1210 ​-pound force.

Answer 1

Two forces are given at 15 degree and the equilibrant is required between them

The formula to find the equilibrant is given by

So the magnitude of equilibrant is 2726.8 lb

now in order to find the angle with respect to 1210 lb we can say

`\phi = tan^(-1)(1540sin\theta)/(1210 + 1540cos\theta)`

`\phi = tan^(-1)0.147`

`\phi = 8.4 degree`