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PLEASE HELP ASAP BIG POINTS

The projectile motion of an object can be modeled using s(t) = gt2 + v0t + s0, where g is the acceleration due to gravity, t is the time in seconds since launch, s(t) is the height after t seconds, v0 is the initial velocity, and s0 is the initial height. The acceleration due to gravity is –4.9 m/s2.

An object is launched at an initial velocity of 19.6 meters per second from an initial height of 24.5 meters. Which equation can be used to find the number of seconds it takes the object to hit the ground?

0 = –4.9t2 + 19.6t + 24.5
0 = –4.9t2 + 24.5t + 19.6
19.6 = –4.9t2 + 24.5t
24.5 = –4.9t2 + 19.6t

User ShlomiF
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2 Answers

3 votes

Answer:

its A!!!

Explanation:

User JustAndrei
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8.9k points
5 votes

We are given the equation:

s(t) = gt² + v₀t + s₀

g=-4.9, v₀ =19.6 and s₀=24.5

plugging these values in the equation we get,

s(t)=-4.9t² +19.6t +24.5

Non when it hits the ground final height s(t) will be 0

0=-4.9t² +19.6t +24.5

first option is correct

User Gaurav S
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