Question

What is the distance and midpoint of (-2,2)(2,-3)

Answer 1

`\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\(\stackrel{x_1}{-2}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{-3})\qquad \qquad d = √(( x_2- x_1)^2 + ( y_2- y_1)^2)\\\\\\d=√([2-(-2)]^2+[-3-2]^2)\implies d=√((2+2)^2+(-3-2)^2)\\\\\\d=√(4^2+(-5)^2)\implies d=√(41)`

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