Part A
After dividing the first two terms by the coefficient of n², the coefficient of the linear term is -6, so we can complete the square by adding (and subtracting) the square of half that: (-6/2)² = 9.
... g(n) = n² -6n + 9 + 16 - 9
... g(n) = (n -3)² +7 . . . . . . . rewrite to vertex form
Part B
The generic vertex form is
... y = a(x -h)² +k . . . . . . for vertex (h, k) and vertical expansion factor "a"
Comparing this to g(n), we see a=1, h=3, k=7. When a > 0, the parabola opens upward, and the vertex is a minimum. Here, we have a > 0, so we can conclude ...
... the vertex (3, 7) is a minimum
Part C
The axis of symmetry is the vertical line through the vertex.
... x = 3