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Find the value of cot (theta) for an angle (theta) in standard position with a terminal ray that passes through the point (-9,-5). a. 5/9 b.5/(sqrt 106) c. 9/5 d. 9/(sqrt 106)

Find the value of cot (theta) for an angle (theta) in standard position with a terminal ray that passes through the point (-9,-5). a. 5/9 b.5/(sqrt 106) c. 9/5 d. 9/(sqrt 106)
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Find the value of cot (theta) for an angle (theta) in standard position with a terminal ray that passes through the point (-9,-5).

a. 5/9

b.5/(sqrt 106)

c. 9/5

d. 9/(sqrt 106)

User Johnetta
by
8.3k points

1 Answer

2 votes


P(x,\ y),\ r=√(x^2+y^2)\\\\\cos\theta=(x)/(r)


(-9,\ -5)\to x=-9,\ y=-5\\\\r=√((-9)^2+(-5)^2)=√(81+25)=√(106)\\\\\cos\theta=(-9)/(√(106))

User Nam
by
7.5k points
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