Question

How would the expression x^3-8 be written using difference of cubes

Answer 1

`a^3 - b^3 = (a - b)(a^2 + ab + b^2)`

`x^3 - 8 =`

`= x^3 - 2^3`

`= (x - 2)(x^2 + x(2) + 2^2)`

`= (x - 2)(x^2 + 2x + 4)`

Answer: (x - 2)(x^2 + 2x + 4)

Answer 2

we can use formula

`a^3-b^3=(a-b)(a^2+ab+b^2)`

we can compare

we get

a=x

b=2

now, we can plug that in formula

and we get

`x^3-2^3=(x-2)(x^2+2x+2^2)`

now, we can simplify it

`x^3-8=(x-2)(x^2+2x+4)`...........Answer