We see that terms in given sequence increases by 9 continuously so that means this is an arithmetic progression (AP)
so we will use nth term formula of AP to find the a14
a_n=a_1+(n-1)d
n=14 because we need a14
a1= first term = 2
d = common difference = 11-2=9
Now plug these values into formula
![a_n=a_1+(n-1)d](https://img.qammunity.org/2019/formulas/mathematics/college/fvodfb6s8v2zc0d7kyp2lhqq8hr5hv5s8t.png)
![a_(14)=2+(14-1)(9)](https://img.qammunity.org/2019/formulas/mathematics/high-school/qyngqtm4o0o3h2ygam6t5lud14pok0msxz.png)
![a_(14)=2+(13)(9)](https://img.qammunity.org/2019/formulas/mathematics/high-school/pnojk2netrf3etd656luq5kf0cqnc2s48d.png)
![a_(14)=2+117](https://img.qammunity.org/2019/formulas/mathematics/high-school/9hzyp6w884cjobv2vjpyjncu7w81k6fp4r.png)
![a_(14)=119](https://img.qammunity.org/2019/formulas/mathematics/high-school/ckzl4iecspk9qhvwjauqtyn1aa8y0417ai.png)
So the final answer is
![a_(14)=119](https://img.qammunity.org/2019/formulas/mathematics/high-school/ckzl4iecspk9qhvwjauqtyn1aa8y0417ai.png)