Question

Turner is deep-sea diving with two friends. Janelle is floating on the surface 15 meters above

Turner, and Ethan is exploring a coral reef 8 meters in front of Turner. How far apart are
Janelle and Ethan?

Answer 1

Using the Pythagorean theorem, we determine that Janelle and Ethan are 17 meters apart. The theorem is applied by adding the squares of the vertical and horizontal distances between them and taking the square root of the sum.

Step-by-step explanation:

The question relates to finding the distance between two points in a three-dimensional space, which is a topic in geometry, a branch of mathematics. To solve the problem, we must visualize the scenario as a right-angled triangle where Janelle is 15 meters above Turner, vertically, and Ethan is 8 meters away from Turner, horizontally.

By using the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides, we can calculate the distance between Janelle and Ethan as follows:

1. Firstly, we identify the two known sides of the triangle:
   
   • The distance from Turner to Janelle is 15 meters (vertical side).
   • The distance from Turner to Ethan is 8 meters (horizontal side).
2. Then, we apply the Pythagorean theorem:
   
   • C^2 = A^2 + B^2, where
     
     • C is the hypotenuse (the distance between Janelle and Ethan),
     • A is the vertical side (15 meters), and
     • B is the horizontal side (8 meters).
   • After calculation, we find that C^2 = 15^2 + 8^2, which simplifies to C^2 = 225 + 64, and further simplifies to C^2 = 289. Therefore, C (the distance between Janelle and Ethan) equals the square root of 289, which is 17 meters.

Thus, Janelle and Ethan are 17 meters apart.

Answer 2

23 because if u add bothe of them up