Question

Solve the following equations

2(3x - 1) + 2(4x+5) =8

Answer 1

x = 0

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• Work

`2\left(3x-1\right)+2\left(4x+5\right)=8\\2\left(3x-1\right)+2\left(4x+5\right)\\2\cdot \:3x-2\cdot \:1\\2\cdot \:3=6\\2\cdot \:1=2\\=6x-2\\=6x-2+2\left(4x+5\right)\\2\left(4x+5\right)\\2\cdot \:4x+2\cdot \:5\\2\cdot \:4=8\\2\cdot \:5=10\\=8x+10\\=6x-2+8x+10\\6x+8x-2+10\\14x-2+10\\14x+8\\14x+8=8\\14x+8-8=8-8\\14x=0\\(14x)/(14)=(0)/(14)\\x = 0`

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Answer 2

x = 0

Explanation:

Given equation,

→ 2(3x - 1) + 2(4x + 5) = 8

Now the value of x will be,

→ 2(3x - 1) + 2(4x + 5) = 8

→ 6x - 2 + 8x + 10 = 8

→ 14x + 8 = 8

→ 14x = 8 - 8

→ x = 0/14

→ [ x = 0 ]

Hence, the value of x is 0.