Question

4720 kJ of energy are supplied to a material in order to raise its temperature by 65K. If the specific heat capacity of the material is 2730 J kg-1 K-1 then what is its mass?

Answer 1

the answer is 26.6 kj

Step-by-step explanation:

because i took a test with the same question and the answer was 26.6kj

Answer 2

Answer : The correct answer for mass of material = 26.6 Kg

Given : Q = 4720 KJ

Change in Temperature ( ΔT ) = 65 K

Specific heat capacity of material ( c) = 2730
`(J)/(Kg* K)`

The relation between Q , ΔT , c and m are related by following formula :

Q = m* c*ΔT ,

where Q = Heat or energy absorbed or released

m = mass , c = specific heat ,ΔT = change in Temperature

Plugging value in heat formula :

`4720 KJ = m * 2730 (J)/(Kg * K) * 65 K`

`image`

[[Converting
`177450 (J)/(Kg) to (KJ)/(Kg)`

`177450 (J)/(Kg) * (1 KJ)/(1000 J) = 177.450 (KJ)/(Kg)` ]]

Dividing both side by
`177.450 (KJ)/(Kg)`

`(4720 KJ)/(177.450 (KJ)/(Kg)) = m * (177.450(KJ)/(Kg) )/(177.450(KJ)/(Kg) )`

m = 26.6 Kg