Let's try to simplify that a bit. Rewriting it in its current form it looks like this:
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We could split it up and deal with one problem at a time if we do this:
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The rule with like bases and division of the exponents is that we subtract the lower exponent from the upper so that would be
![x^(3-(-2))*y^(-2-3)](https://img.qammunity.org/2019/formulas/mathematics/high-school/pju8ahiwi4onug3mf1bl0edlv7wlgovfod.png)
which gives us new exponents of
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We rewrite to make that negative exponent a positive by putting it under a 1, so the whole problem with no negatives looks like this now:
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If x = 2 and y = 3, we sub in accordingly:
![(3(2)^5)/(5(3)^5) =(3(32))/(5(243))](https://img.qammunity.org/2019/formulas/mathematics/high-school/w3ze7y16z94v8574fb7nn3ddnnkrimi4mq.png)
which simplifies to
, the first choice above.