Hello!
This question is referring to reference angles.
In Quadrant I, then 0° < θ < 90°.
In Quadrant II, then 90° < θ < 180°.
In Quadrant III, then 180° < θ < 270°.
In Quadrant IV, then 270° < θ < 360°.
Here are the reduction formulas:
In Quadrant I: θ (The angle doesn't change because in Q1, the angle is acute.)
In Quadrant II: (180 - θ)
In Quadrant III: (180 + θ)
In Quadrant IV: (360 - θ).
Since sec 120° is located in quadrant one, we use the reduction formula: (180 - θ).
(180 - 120) = 60°
Therefore, the angle that can be used to evaluate sec 120°, is C, 60°.