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I need quick! 20 points!

Use the functions h(x) = 4x − 5 and t(x) = 2x + 4 to complete the function operations listed below.

Part A: Find (h + t)(x). Show your work. (3 points)

Part B: Find (h ⋅ t)(x). Show your work. (3 points)

Part C: Find h[t(x)]. Show your work. (4 points)


What i have so far, idk if im right

(4x-5) + (2x+4)
6x-1(x)
5x

I need help on the rest and i need to know if i did the first one right

User Gogonapel
by
7.8k points

1 Answer

3 votes
Given is h(x) = 4x − 5 and t(x) = 2x + 4.

Part A: Finding (h + t)(x)

(h + t)(x) = (4x - 5) + (2x + 4) \\ (h + t)(x) = 4x - 5 + 2x + 4 \\ (h + t)(x) = 4x + 2x - 5 + 4 \\ (h + t)(x) = 6x - 1

Part B: Finding​ (h ⋅ t)(x)

(h ⋅ t)(x) = (4x - 5)(2x + 4) \\ (h ⋅ t)(x) = 4x(2x + 4) - 5(2x + 4) \\ (h ⋅ t)(x) = 8 {x}^(2) + 16x - 10x - 20 \\ (h ⋅ t)(x) = 8 {x}^(2) + 6x - 20
Part C: Finding h[t(x)]

h[t(x)] = 4 * t(x) - 5 \\ h[t(x)] = 4(2x + 4) - 5 \\ h[t(x)] = 8x + 16 - 5 \\ h[t(x)] = 8x + 11

User Jmvbxx
by
7.9k points

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