The question is typed wrong. The correct question is
Balance the following equation. Then determine the mole ratio of Ca(OH)2:Al(OH)3.
Al2(SO4)3 + Ca(OH)2 --> Al(OH)3 + CaSO4
Answer:-
Al2(SO4)3 + 3 Ca(OH)2 = 2 Al(OH)3 + 3 CaSO4
3: 2
Explanation:-
Al2(SO4)3 + Ca(OH)2 --> Al(OH)3 + CaSO4
In the left hand side there are 3 S atoms from Al2(SO4)3
But in the right side there is only 1 S from CaSO4.
To make the right side same we multiply the CaSO4 by 3.
Al2(SO4)3 + Ca(OH)2 --> Al(OH)3 + 3 CaSO4
Now in the right side there 3 Ca from 3 CaSO4.
But in the left side there is only 1 Ca from Ca(OH)2.
To make it same we multiply Ca(OH)2 by 3.
Al2(SO4)3 + 3 Ca(OH)2 --> Al(OH)3 + 3 CaSO4
Now there 2 Al from Al2(SO4)3 on the left.
But there is only 1 Al from Al(OH)3.
So we multiply Al(OH)3 by 2.
Al2(SO4)3 + 3 Ca(OH)2 --> 2 Al(OH)3 + 3 CaSO4
Now we have 12 + 6 = 18 O on the left.
On the right we have 6 + 12 = 18 O atoms.
On the left we have 6 H atoms.
On the right we have 6 H atoms.
So our equation is balanced.
From the balanced equation
Al2(SO4)3 + 3 Ca(OH)2 --> 2 Al(OH)3 + 3 CaSO4
Ratio of Ca(OH)2 to Al(OH)3 = 3 : 2