Question

Identify the vertex of f(x)=

`{(x - 5)}^(2) - 3`

Answer 1

The given equation is in what we know as "vertex form".

In this form, the equation enters the order of
`f(x) = a(x - h)^2 + k`, where vertex is
`(h,k)`.

In this case, we have
`(x-5)` for
`(x-h)`and for
`k` we have
`-3`. So, the vertex is
`(5, -3)`

Answer 2

If the quadratic is written in the form

`y=a(x-h)^(2) +k`

then the vertex is the point (h, k).

So from our equation,

`f(x)=(x-5)^(2) -3`

here on comparing our equation with the vertex form we get ,

h=5 and k=-3

vertex (5,-3)