Question

In the tollowing combustion reaction of acetylene (C2H2), how many lters of CO2 will be produced it 60 liters of 02 is used, given that both gases are at STP?

Answer 1

Under STP 1 mol of gas has volume 22.4 L.

2C2H2 + 5O2 ------> 4CO2 + 2H2O

from reaction 5*22.4 L 4 *22.4L

given 60L x L

x=(60*4 *22.4)/5*22.4 = (60*4)/5 =48 L of CO2