Question

Find the quotient of quantity of 4 times x to the 3rd power minus 12 times x to the 2nd power plus 8 times x all over negative 4 times x. −x2 + 3x − 2 x2 − 12x + 4 −x2 − 3x + 2 x2 + 12x − 4

Answer 1

`\displaystyle (4x^3-12x^2+8x)/(-4x)=(4x^3)/(-4x)+(-12x^2)/(-4x)+(8x)/(-4x)\\\\=-x^2+3x-2`

This result corresponds to the first selection.