Question

Plzzzzzzzzzz answer for the 2nd question plz I beg of u

Answer 1

2)

`\bf 2x^2+3√(5)x+5~~\begin{cases}5=&√(5)\cdot √(5)\\3√(5)=&2√(5)+√(5)\end{cases}\implies \left( 2x+√(5) \right)\left(x+√(5) \right)`

3)

let's keep in mind that

1² = 1

1³ = 1

1⁴ = 1

1¹⁰⁰⁰⁰⁰⁰⁰⁰ = 1

`\bf x^4-5x^2+4\implies (x^2)^2-5x^2+4~~\begin{cases}-5x^2=&-4x^2-x^2\\4=&-4\cdot -1\end{cases}\\\\\\(x^2-4)(x^2-1)\implies \stackrel{\textit{difference of squares on both}}{(x^2-2^2)(x^2-1^2)}\\\\\\(x-2)(x+2)(x-1)(x+1)`