Answer:
D. 1 × 10–3 C
Step-by-step explanation:
I just took it
Amount of charge on the capacitor=q=10⁻³C
Energy stored=4.5x10⁻³ J
potential difference= 9 V
Energy stored= E= 1/2 q V
4.5x10⁻³ =1/2 q (9)
q=10⁻³C
Thus the amount of charge on the capacitor=q=10⁻³C
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