Question

a given sample of a gas has a volume of 3.0 L at a pressure of 4.0 atm. If the temperature remains constant and the pressure is changed to 6.0 atm, what is the new volume?

Answer 1

Answer:-

2.0 L

Explanation:-

Initial Volume = V 1 = 3.0 L

Initial Pressure P 1 = 4.0 atm

New pressure P 2 = 6.0 atm

Using boyle's law

P1 V1 = P2 V2

New Volume V2 = P1 V1 / P2

= 4.0 atm x 3.0 L / 6.0 atm

= 2 .0 L