A) (f + g)(x) = f(x) + g(x) = (5x-12) + (11x+2) = 16x-10
B) (f × g)(x) = f(x)×g(x) = (5x-12)×(11x+2) = 5x(11x) -12(11x)+2(5x) -12(2) = 55x² -122x -24
C) f(g(x)) = 5(11x+2) -12 . . . . substitute g(x) for the x in f(x)
... = 55x +10 -12 = 55x -2
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