Question

Until a train is a safe distance from the station it must travel at 5 m/s. Once the train is on open track it can speed up to 45 m/s. If it takes a train 8 seconds to reach 45 m/s, what is the acceleration of the train? (Round your answer to the nearest whole number.)

4 m/s2
5 m/s2
6 m/s2
7 m/s2

Answer 1

B. 5 m/s2

Step-by-step explanation:

Answer 2

the acceleration of the train is 5 m/s²

Step-by-step explanation:

initial velocity= Vi= 5 ms

final velocity= Vf= 45 m/s

time= t= 8 seconds

using kinematic equation Vf= Vi +at

45= 5+a (8)

8 a = 45=5

8a= 40

a= 40/8

a= 5m/s²

So the acceleraton of the train is 5m/s²