Answer: The required values of x are
x = 4, -4.
Step-by-step explanation: We are given to find the values of x that are the solutions to the following equation :
![15x^2-56=88+6x^2~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)](https://img.qammunity.org/2019/formulas/mathematics/high-school/4o7lux4o5vhb9jc1uc1wuweeci65cc65n1.png)
Since the above quadratic equation (i) does not contain term involving x, so we will be solving the equation by square root method.
The solution of equation (i) is as follows :
![15x^2-56=88+6x^2\\\\\Rightarrow 15x^2-6x^2=88+56\\\\\Rightarrow 9x^2=144\\\\\Rightarrow x^2=(144)/(9)\\\\\Rightarrow x^2=16\\\\\Rightarrow x=\pm√(16)~~~~~~~~~~~[\textup{taking square root on both sides}]\\\\\Rightarrow x=\pm4.](https://img.qammunity.org/2019/formulas/mathematics/high-school/x59dncrn3u9c1zt9arf2oxqi2a6e25t5jp.png)
Thus, the required values of x are
x = 4, -4.