Evaluate cos11pi /6 -square root of 3/2 -1/2 1/2 square root of 3/2

asked Apr 22, 2019 189k views

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Evaluate cos11pi /6
-square root of 3/2
-1/2
1/2
square root of 3/2

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1 vote

$\displaystyle cos (11 \pi)/(6)= cos ((3 \pi)/(2) + ( \pi)/(3))=sin ( \pi)/(3)= sin 60^(\circ)=( \sqrt3)/(2)$

Answer is 4) square root of 3 / 2

AhmadWabbi answered Apr 29, 2019

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