I must assume that you meant 2x - 3y = 9.
A line parallel to this line has exactly the same format, but a different constant on the right: 2x - 3y = c. Substituting the given values of x and y, we get:
2(4) - 3(-1) = 8+3 = 11. Thus, c = 11, and the equation of the new parallel line is
11 - 2x
2x - 3y = 11. Solving for y, -3y = 11 - 2x, or y = -------------
-3
so the slope of the parallel lilnes is 2/3.
A line perpendicular to the given line has a slope which is the negative reciprocal of 2/3: -3/2.
This perpendicular line has the equation
y + 1 = (-3/2)(x-4) (point-slope form), or
2y + 2 = -3(x-4) = -3x + 12. Then 2y = -3x + 12, and y = (-3/2)x + 6 (the perpendicular line's equation)