Question

Isopropyl alcohol is mixed with water to produce a 37.0% (v/v) alcohol solution. how many milliliters of each component are present in 835 ml of this solution? (assume that volumes are additive.)

Answer 1

Answer: -

Isopropyl alcohol = 308.95mL

Water = 526.05 mL

Explanation: -

Total volume = 835 mL

Percentage of Isopropyl alcohol = 37%

Volume of Isopropyl alcohol =
`(37)/(100) x` 835 mL

= 308.95 mL

Since volumes are additive,

Volume of water = Total volume - Volume of Isopropyl alcohol

= 835 - 308.95

= 526.05 mL

Thus, if Isopropyl alcohol is mixed with water to produce a 37.0% (v/v) alcohol solution. 526.05 mL water and 308.95 mL isopropyl alcohol are present in 835 ml of the solution (assuming that volumes are additive).